1,2

Paul Tek, Table of n, a(n) for n = 1..300

a(n+1) = A256508^n(n+1) for any n>=0 (where A256508^n denotes the n-th iterate of A256508).

a(3) = A256508^2(3) = A256508(A256508(3)) = A256508(6) = 9.

Cf. A256508.

Sequence in context: A135044 A236854 A235491 * A064505 A253288 A048798

Adjacent sequences: A256510 A256511 A256512 * A256514 A256515 A256516

nonn

Paul Tek, Apr 01 2015

approved