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 A255565 a(0) = 0; for n >= 1: if n = A255411(k) for some k, then a(n) = 2*a(k), otherwise, n = A256450(h) for some h, and a(n) = 1 + 2*a(h). 6
 0, 1, 3, 7, 2, 15, 5, 31, 11, 63, 23, 127, 6, 47, 255, 13, 14, 95, 4, 511, 27, 29, 30, 191, 9, 1023, 55, 59, 61, 383, 19, 2047, 111, 119, 123, 767, 39, 4095, 223, 239, 247, 1535, 79, 8191, 447, 479, 495, 3071, 10, 159, 16383, 895, 62, 959, 991, 6143, 21, 319, 32767, 1791, 22, 125, 1919, 1983, 126, 12287, 46, 43, 639, 65535, 254, 3583, 12 (list; graph; refs; listen; history; text; internal format)
 OFFSET 0,3 COMMENTS Because all terms of A255411 are even it means that even terms can only occur in even positions (together with some odd terms, for each one of which there is a separate infinite cycle), while terms in odd positions are all odd. LINKS Antti Karttunen, Table of n, a(n) for n = 0..5040 FORMULA a(0) = 0; for n >= 1: if A257680(n) = 0 [i.e., n is one of the terms of A255411], then a(n) = 2*a(A257685(n)), otherwise [when n is one of the terms of A256450], a(n) = 1 + 2*a(A273662(n)). Other identities: For all n >= 1, A001511(a(n)) = A257679(n). For all n >= 1, a(A001563(n)) = A000079(n-1) = 2^(n-1). For all n >= 1, a(A000142(n)) = A083318(n-1). PROG (Scheme, with memoization-macro definec) (definec (A255565 n) (cond ((zero? n) n) ((zero? (A257680 n)) (* 2 (A255565 (A257685 n)))) (else (+ 1 (* 2 (A255565 (A273662 n))))))) CROSSREFS Inverse: A255566. Cf. A000079, A000142, A001511, A001563, A083318, A255411, A256450, A257679, A257680, A257682, A257685. Cf. also arrays A257503, A257505. Related or similar permutations: A273665, A273668. Sequence in context: A266417 A260433 A243343 * A227351 A246377 A260421 Adjacent sequences:  A255562 A255563 A255564 * A255566 A255567 A255568 KEYWORD nonn,base AUTHOR Antti Karttunen, May 05 2015 EXTENSIONS Formula changed because of the changed starting offset of A256450 - Antti Karttunen, May 30 2016 STATUS approved

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Last modified February 24 01:03 EST 2020. Contains 332195 sequences. (Running on oeis4.)