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A255405
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a(n) = floor((2/sqrt(Pi))^n).
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2
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1, 1, 1, 1, 1, 2, 2, 2, 2, 3, 3, 4, 4, 5, 6, 6, 7, 8, 9, 11, 12, 14, 16, 18, 20, 23, 26, 29, 33, 37, 42, 47, 53, 60, 68, 77, 87, 98, 111, 125, 141, 159, 180, 203, 229, 258, 292, 329, 371, 419, 473, 534, 602, 680, 767, 865, 977, 1102, 1244, 1403, 1584, 1787, 2016, 2275, 2567
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OFFSET
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0,6
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COMMENTS
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Inspired by squaring the circle and Vitruvian Man, but starting with a unit circle and a square whose sides are of length sqrt(Pi), A002161. a(n) is the nested circle curvature (rounded down) after n iterations. See illustrations in the links.
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LINKS
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FORMULA
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a(n) = floor((2/sqrt(Pi))^n).
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MATHEMATICA
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Table[Floor[(2/Sqrt[Pi])^n], {n, 0, 50}] (* G. C. Greubel, Jan 09 2017 *)
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PROG
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(PARI){for(n=1, 100, a=floor(2^n/sqrt(Pi)^n); print1(a, ", "))}
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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