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A254637
Maximal element of Image^inf({ 2 }) under repeated base-n zero-split doubling.
2
2, 16, 2, 192, 128, 32768, 4, 69632, 23552, 25722880, 425984, 717895680, 1051828224, 217079873536, 8, 2270641389568, 10603200512, 156423849771008, 950175531008, 25160124578398208, 385584983965696, 450589122059304960, 40722497536, 53279734579488838656
OFFSET
2,1
COMMENTS
Define f_b(x) to be the set of base b numbers left after splitting 2x at its zero digits and Image_b(S) = union_{x in S}{ { x } union f_b(S) }, then a(n) = max(Image_n^inf({ 2 }))
LINKS
Hugo van der Sanden, Table of n, a(n) for n = 2..62
Hugo van der Sanden, Perl and C implementations, Feb 03 2015
EXAMPLE
a(8) = 4 since f_8(2) = { 4 }, f_8(4) = { 1 }, f_8(1) = { 2 } so Image_8^inf({ 2 }) = { 1, 2, 4 }.
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Hugo van der Sanden, Feb 03 2015
STATUS
approved