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 A254606 The minimum absolute difference between k*p1 and p2 (p1
 0, 1, 0, 1, 1, 0, 1, 1, 2, 0, 1, 1, 1, 3, 0, 1, 1, 2, 1, 2, 0, 1, 1, 2, 3, 5, 4, 0, 1, 1, 1, 2, 3, 6, 2, 0, 1, 1, 2, 2, 1, 3, 6, 4, 0, 1, 1, 1, 1, 4, 3, 5, 9, 6, 0, 1, 1, 1, 3, 2, 5, 3, 7, 8, 2, 0, 1, 1, 2, 2, 4, 2, 3, 1, 9, 8, 6, 0, 1, 1, 1, 1, 3, 2, 7, 3, 5 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,9 COMMENTS k is an integer that minimizes |k*p1-p2|. It is trivial that if j is the integer part of p2/p1, k is either j or j+1. LINKS Lei Zhou, Table of n, a(n) for n = 1..10000 EXAMPLE A087112(1)=4=2*2, 2-2=0, so a(1)=0; A087112(2)=6=2*3, 3-2=2*2-3=1, so a(2)=1; ... A087112(9)=35=5*7, 7-5=2, and 2*5-7=3, the smaller is 2. So a(9)=2. MATHEMATICA NumDiff[n1_, n2_] :=  Module[{c1 = n1, c2 = n2}, If[c1 < c2, c1 = c1 + c2; c2 = c1 - c2; c1 = c1 - c2]; k = Floor[c1/c2]; a1 = c1 - k*c2; If[a1 == 0, a2 = 0, a2 = (k + 1) c2 - c1]; Return[Min[a1, a2]]]; p1 = 2; p2 = 1; Table[p2 = NextPrime[p2]; If[p2 > p1, p1 = p2; p2 = 2]; NumDiff[p1, p2], {n, 1, 100}] CROSSREFS Cf. A087112, A254605. Sequence in context: A333467 A120648 A215401 * A175358 A235330 A029394 Adjacent sequences:  A254603 A254604 A254605 * A254607 A254608 A254609 KEYWORD nonn,easy AUTHOR Lei Zhou, Feb 02 2015 STATUS approved

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Last modified April 21 15:55 EDT 2021. Contains 343156 sequences. (Running on oeis4.)