%I
%S 1,5,36,280,2201,17325,136396,1073840,8454321,66560725,524031476,
%T 4125691080,32481497161,255726286205,2013328792476,15850904053600,
%U 124793903636321,982500325036965,7735208696659396,60899169248238200,479458145289246201,3774765993065731405
%N Indices of centered triangular numbers (A005448) which are also centered pentagonal numbers (A005891).
%C Also indices of pentagonal numbers (A000326) which are also centered pentagonal numbers (A005891).
%C Also positive integers x in the solutions to 3*x^2  5*y^2  3*x + 5*y = 0, the corresponding values of y being A182432.
%H Colin Barker, <a href="/A253470/b253470.txt">Table of n, a(n) for n = 1..1000</a>
%H <a href="/index/Rec#order_03">Index entries for linear recurrences with constant coefficients</a>, signature (9,9,1).
%F a(n) = 9*a(n1)9*a(n2)+a(n3).
%F G.f.: x*(4*x1) / ((x1)*(x^28*x+1)).
%F a(n) = (6(4sqrt(15))^n*(3+sqrt(15))+(3+sqrt(15))*(4+sqrt(15))^n)/12.  _Colin Barker_, Mar 03 2016
%e 5 is in the sequence because the 5th centered triangular number is 31, which is also the 4th centered pentagonal number.
%o (PARI) Vec(x*(4*x1)/((x1)*(x^28*x+1)) + O(x^100))
%Y Cf. A005448, A005891, A182432, A253654.
%K nonn,easy
%O 1,2
%A _Colin Barker_, Jan 01 2015
