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First quotients of A252738: a(0) = 1; for n >= 1, a(n) = A252738(n) / A252738(n-1).
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%I #4 Dec 23 2014 00:38:04

%S 1,2,6,180,1134000,3465651420000000,

%T 356414438712215830124178000000000000000,

%U 1311750338118625705168608107387873609070899443110750355586669940000000000000000000000000000000

%N First quotients of A252738: a(0) = 1; for n >= 1, a(n) = A252738(n) / A252738(n-1).

%F a(0) = 1; for n >= 1, a(n) = A252738(n) / A252738(n-1).

%o (Scheme) (define (A252740 n) (if (zero? n) 1 (/ (A252738 n) (A252738 (- n 1)))))

%Y Cf. A252738, A252739, A163511.

%K nonn

%O 0,2

%A _Antti Karttunen_, Dec 21 2014