%I
%S 483,1304163,3523847043,9521433405123,25726909536794403,
%T 69514100046985070883,187827072600044124730563,
%U 507508680651219178036909443,1371288267292521619011604583523,3705220390715712763350177547768803,10011504124425588594050560722466721283
%N Numbers n such that the octagonal number N(n) is the sum of three consecutive octagonal numbers.
%C Also nonnegative integers y in the solutions to 18*x^26*y^2+24*x+4*y+18 = 0, the corresponding values of x being A251624.
%C It seems that the least significant digit of each term is 3.
%H Colin Barker, <a href="/A251625/b251625.txt">Table of n, a(n) for n = 1..291</a>
%H <a href="/index/Rec#order_03">Index entries for linear recurrences with constant coefficients</a>, signature (2703,2703,1).
%F a(n) = 2703*a(n1)2703*a(n2)+a(n3).
%F G.f.: 3*x*(x^2462*x+161) / ((x1)*(x^22702*x+1)).
%F a(n) = (1 + 2*(sqrt(3)+2)*(1351+780*sqrt(3))^(n)  2*(sqrt(3)2)*(1351+780*sqrt(3))^n) / 3.  _Colin Barker_, May 30 2017
%e 483 is in the sequence because N(483) = 698901 = 231296+232965+234640 = N(278)+N(279)+N(280).
%o (PARI) Vec(3*x*(x^2462*x+161)/((x1)*(x^22702*x+1)) + O(x^100))
%Y Cf. A000567, A251624.
%K nonn,easy
%O 1,1
%A _Colin Barker_, Dec 06 2014
