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%I #4 Nov 09 2014 17:52:59
%S 15,285,15,2010,505,15,8790,5300,897,15,28785,31180,14094,1593,15,
%T 77595,129095,111746,37584,2825,15,181860,422065,585069,402010,100236,
%U 4999,15,383580,1164800,2319123,2662039,1447334,267004,8823,15,745155,2830080
%N T(n,k)=Number of length n+5 0..k arrays with no six consecutive terms having the maximum of any two terms equal to the minimum of the remaining four terms
%C Table starts
%C .15...285.....2010......8790.......28785........77595........181860
%C .15...505.....5300.....31180......129095.......422065.......1164800
%C .15...897....14094....111746......585069......2319123.......7532380
%C .15..1593....37584....402010.....2662039.....12791191......48882360
%C .15..2825...100236...1447334....12123567.....70617807.....317518832
%C .15..4999...267004...5207128....55191061....389769865....2062131616
%C .15..8823...709814..18707320...251002319...2149795141...13385651492
%C .15.15918..1911823..67741331..1147421312..11899842997...87116453114
%C .15.28655..5149630.245362806..5246484791..65881899243..567055137628
%C .15.51435.13856525.888353351.23984087410.364700648588.3690747006754
%H R. H. Hardin, <a href="/A249960/b249960.txt">Table of n, a(n) for n = 1..873</a>
%F Empirical for column k:
%F k=1: a(n) = a(n-1)
%F k=2: [order 66]
%F Empirical for row n:
%F n=1: a(n) = n^6 + 3*n^5 + 5*n^4 + 5*n^3 + (3/2)*n^2 - (1/2)*n
%F n=2: [polynomial of degree 7]
%F n=3: [polynomial of degree 8]
%F n=4: [polynomial of degree 9]
%F n=5: [polynomial of degree 10]
%F n=6: [polynomial of degree 11]
%F n=7: [polynomial of degree 12]
%e Some solutions for n=3 k=4
%e ..3....4....4....0....0....3....0....0....4....3....2....2....2....0....2....1
%e ..3....1....0....3....3....0....1....0....1....1....4....1....0....4....4....4
%e ..1....4....1....2....4....4....2....3....1....1....1....1....0....3....2....1
%e ..1....1....4....4....4....1....4....1....2....4....3....4....1....1....1....4
%e ..3....0....2....3....0....4....3....3....3....0....3....0....4....0....2....4
%e ..4....0....2....1....3....2....3....4....4....0....3....0....4....4....1....3
%e ..2....3....4....0....1....0....3....3....3....4....0....2....4....4....4....0
%e ..3....2....1....3....4....4....1....0....3....4....0....2....3....2....2....3
%K nonn,tabl
%O 1,1
%A _R. H. Hardin_, Nov 09 2014
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