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A248692 Fully multiplicative with a(prime(i)) = 2^i; If n = Product_{k >= 1} (p_k)^(c_k) where p_k is k-th prime A000040(k) and c_k >= 0 then a(n) = Product_{k >= 1} 2^(k*c_k). 4
1, 2, 4, 4, 8, 8, 16, 8, 16, 16, 32, 16, 64, 32, 32, 16, 128, 32, 256, 32, 64, 64, 512, 32, 64, 128, 64, 64, 1024, 64, 2048, 32, 128, 256, 128, 64, 4096, 512, 256, 64, 8192, 128, 16384, 128, 128, 1024, 32768, 64, 256, 128, 512, 256, 65536, 128, 256, 128, 1024, 2048, 131072, 128, 262144, 4096, 256, 64 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,2
COMMENTS
Equally, if n = p_i * p_j * ... * p_k, where p_i, p_j, ..., p_k are the primes A000040(i), A000040(j), ..., A000040(k) in the prime factorization of n (indices i, j, ..., k not necessarily distinct), then a(n) = 2^i * 2^j * 2^k.
a(1) = 1 (empty product).
Fully multiplicative with a(prime(i)) = 2^i.
LINKS
FORMULA
a(n) = 2^A056239(n) = A000079(A056239(n)).
Other identities. For all n >= 1:
a(A122111(n)) = a(n).
a(A000040(n)) = A000079(n).
For all n >= 0:
a(A000079(n)) = A000079(n).
a(n) = Product_{d|n} 2^A297109(d). - Antti Karttunen, Feb 01 2021
Sum_{n>=1} 1/a(n) = A065446. - Amiram Eldar, Dec 24 2022
MAPLE
a:= n-> mul((2^numtheory[pi](i[1]))^i[2], i=ifactors(n)[2]):
seq(a(n), n=1..64); # Alois P. Heinz, Jan 14 2021
MATHEMATICA
a[n_] := Product[{p, e} = pe; (2^PrimePi[p])^e, {pe, FactorInteger[n]}];
Array[a, 100] (* Jean-François Alcover, Jan 03 2022 *)
PROG
(MIT/GNU Scheme, with Aubrey Jaffer's SLIB Scheme library)
(require 'factor)
(define (A248692v2 n) (apply * (map A000079 (map A049084 (factor n)))))
;; Alternatively:
(define (A248692 n) (A000079 (A056239 n)))
(PARI) A248692(n) = if(1==n, n, my(f=factor(n)); for(i=1, #f~, f[i, 1] = 2^primepi(f[i, 1])); factorback(f)); \\ Antti Karttunen, Feb 01 2021
CROSSREFS
Sequence in context: A366665 A166632 A116596 * A048656 A107848 A285273
KEYWORD
nonn,mult
AUTHOR
Antti Karttunen, Oct 11 2014
STATUS
approved

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Last modified April 24 19:06 EDT 2024. Contains 371962 sequences. (Running on oeis4.)