

A248548


Sums of Pythagorean sextuplets in increasing order: The sums of sets of six natural numbers which correspond to the lengths of the edges of a tetrahedron whose four faces are all different Pythagorean triangles.


1



2491, 3616, 4385, 4450, 4783, 4982, 7232, 7473, 7974, 8770, 8900, 9566, 9964, 10848, 11784, 12455, 12503, 13155, 13350, 13565, 14086, 14141, 14349, 14464, 14778, 14946, 15948, 16389, 17394, 17437, 17540, 17800, 18080, 19132, 19453, 19928, 21696, 21925, 22250, 22419, 22821, 23568, 23915, 23922, 24079
(list;
graph;
refs;
listen;
history;
text;
internal format)



OFFSET

1,1


COMMENTS

A Pythagorean sextuplet contains four Pythagorean triples.
The sequence is sorted on increasing sum of set.
See attached afile to see the specific values in the sets.
The first sum shared by two sets is 956670.
The first set contains the values 104, 153, 672, 185, 680, 697.
The first set to have a ratio less than 2:1 between its highest and lowest value is 1680, 1925, 2052, 2555, 2652, 3277.
The method used for finding the sets was to connect two Pythagorean triangles along one edge and then calculate the length of the remaining edge.


LINKS

Andreas Boe, Table of n, a(n) for n = 1..2426
Andreas Boe, Sets of Pythagorean sextuples, cross indexed with the base sequence


FORMULA

sum(n) = a(n)+b(n)+c(n)+d(n)+e(n)+f(n).
a^2+b^2=d^2, a^2+c^2=e^2, b^2+e^2=f^2, c^2+d^2=f^2.


EXAMPLE

The first value in the sequence: 2491.
104^2+153^2=185^2, 104^2+672^2=680^2, 153^2+680^2=697^2, 672^2+185^2=697^2;
104+153+185+672+680+697=2491.


CROSSREFS

Sequence in context: A254839 A231456 A190414 * A252315 A131523 A307764
Adjacent sequences: A248545 A248546 A248547 * A248549 A248550 A248551


KEYWORD

nonn


AUTHOR

Andreas Boe, Oct 08 2014


STATUS

approved



