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Numbers k such that A248148(k+1) = A248148(k).
2

%I #4 Oct 02 2014 22:36:49

%S 6,12,17,22,27,32,37,42,47,52,57,62,67,72,77,82,87,92,97,102,107,112,

%T 116,121,126,131,136,141,146,151,155,160,165,170,175,180,185,190,194,

%U 199,204,209,214,219,224,228,233,238,243,248,253,258,262,267,272,277

%N Numbers k such that A248148(k+1) = A248148(k).

%H Clark Kimberling, <a href="/A248149/b248149.txt">Table of n, a(n) for n = 1..400</a>

%t z = 400; p[k_] := p[k] = Sum[1/Binomial[2 h, h], {h, 1, k}] ; r = 1/3 + 2 Pi/Sqrt[243];

%t N[Table[r - p[n], {n, 1, z/50}]]

%t f[n_] := f[n] = Select[Range[z], r - p[#] < 1/3^n &, 1]

%t u = Flatten[Table[f[n], {n, 1, z}]] (* A248148 *)

%t v = Flatten[Position[Differences[u], 0]] (* A248149 *)

%Y Cf. A248148, A248111.

%K nonn,easy

%O 1,1

%A _Clark Kimberling_, Oct 02 2014