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A247239
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Array a(n,m) = ((n+2)/2)^m*Sum_{k=1..n+1} 1/sin(k*Pi/(n+2))^(2m), n>=0, k>=0, read by ascending antidiagonals.
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0
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1, 2, 1, 3, 4, 1, 4, 10, 8, 1, 5, 20, 36, 16, 1, 6, 35, 120, 136, 32, 1, 7, 56, 329, 800, 528, 64, 1, 8, 84, 784, 3611, 5600, 2080, 128, 1, 9, 120, 1680, 13328, 42065, 40000, 8256, 256, 1, 10, 165, 3312, 42048, 241472, 499955, 288000, 32896, 512, 1
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OFFSET
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0,2
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COMMENTS
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Unexpectedly, it is conjectured (proof wanted) that the expression ((n+2)/2)^m * Sum_{k=1..n+1} 1/sin(k*Pi/(n+2))^(2m), n>=0, k>=0, always gives an integer.
For example, a(3,1) = (5/2)*(1/sin(Pi/5)^2 + 1/sin((2*Pi)/5)^2 + 1/sin((3*Pi)/5)^2 + 1/sin((4*Pi)/5)^2) = (5/2)*(2/(5/8 - sqrt(5)/8) + 2/(5/8 + sqrt(5)/8)), which simplifies to 20.
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LINKS
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FORMULA
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First formulas for rows:
a(0,m) = 1.
a(1,m) = 2^(m + 1).
a(2,m) = 2^m + 2^(2*m + 1).
a(3,m) = 2*((5 - sqrt(5))^m + (5 + sqrt(5))^m).
a(4,m) = 2^(2*m + 1) + 3^m + 2^(2*m + 1)*3^m.
First formulas for columns:
a(n,0) = n + 1.
a(n,1) = (n + 1)*(n + 2)*(n + 3)/6.
a(n,2) = coefficient of x^n in the expansion of (1 - x^4)/(1 - x)^8.
Let b(N,m) be (N/2)^m times the coefficient of x^(2*m) in 1-N*x*cot(N*arcsin(x))/ sqrt(1-x^2). Then for m>0, a(n,m) = b(n+2,m). - Ira M. Gessel, Apr 04 2023
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EXAMPLE
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Array a(n,m) begins:
1, 1, 1, 1, 1, 1, 1, 1, ... 1 (A000012)
2, 4, 8, 16, 32, 64, 128, 256, ... 2^(m+1) (A000079)
3, 10, 36, 136, 528, 2080, 8256, 32896, ... A007582
4, 20, 120, 800, 5600, 40000, 288000, 2080000, ... A093123
5, 35, 329, 3611, 42065, 499955, 5980889, 71698571, ... not in the OEIS
...
3rd column is not in the OEIS.
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MATHEMATICA
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a[n_, m_] := ((n + 2)/2)^m*Sum[1/Sin[k*(Pi/(n + 2))]^(2*m), {k, 1, n + 1}]; Table[a[n - m, m] // FullSimplify, {n, 0, 10}, {m, 0, n}] // Flatten
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PROG
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(PARI) a(n, m)={t=Pi/(n+2); u=1+n/2; round(sum(k=1, n+1, (u/sin(k*t)^2)^m))} \\ M. F. Hasler, Dec 03 2014
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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