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A247077
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Composite numbers for which the harmonic mean of proper divisors is an integer.
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3
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OFFSET
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1,1
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COMMENTS
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Of course, for all prime numbers the harmonic mean of proper divisors is an integer.
Conjecture: all terms are of the form m*(sigma(m)-1) where sigma(m)-1 is prime. - Chai Wah Wu, Dec 15 2020
Other terms of the sequence of the form m*(sigma(m)-1) correspond to the following values of m:
3 * 5^143
3 * 5^623
3 * 5^1423
5 * 7^127
5 * 7^6595
101 * 103^25
(End)
Equivalently, composite numbers k such that sigma(k)-1 divides k*(tau(k)-1), where sigma = A000203 and tau = A000005. - Daniel Suteu, Feb 05 2021
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LINKS
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EXAMPLE
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The proper divisors of 1645 are [1,5,7,35,47,235,329] and their harmonic mean is 7/(1/1 + 1/5 + 1/7 + 1/35 + 1/47 + 1/235 + 1/329) = 5.
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MATHEMATICA
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Select[Range[2, 100000], (IntegerQ[HarmonicMean[Most[Divisors[#]]]] && Not[PrimeQ[#]])&] (* Daniel Lignon, Nov 17 2014 *)
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PROG
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(PARI) lista(nn) = forcomposite (n=2, nn, my(d=divisors(n)); if (denominator((#d-1)/sum(i=1, #d-1, 1/d[i])) == 1, print1(n, ", "))); \\ Michel Marcus, Nov 17 2014
(PARI) isok(n) = n > 1 && !isprime(n) && (n*(numdiv(n)-1)) % (sigma(n)-1) == 0; \\ Daniel Suteu, Feb 05 2021
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CROSSREFS
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Cf. A001599 for harmonic mean of all divisors and A247078 for harmonic mean of nontrivial divisors.
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KEYWORD
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nonn,more,bref
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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