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A246819 Max_{2<=k<=n} floor(A242719(k)/prime(k)) - prime(n). 5

%I #11 Sep 13 2014 14:42:19

%S 0,0,0,4,2,4,2,13,7,13,7,4,2,0,17,11,9,6,2,24,21,17,11,12,8,6,2,18,29,

%T 15,11,5,3,16,14,8,18,14,8,22,20,10,30,29,27,15,3,6,8,4,0,30,20,14,60,

%U 54,52,46,42,40,30,16,12,10,41,27,21,11,20,16,10,6

%N Max_{2<=k<=n} floor(A242719(k)/prime(k)) - prime(n).

%C Conjecture: a(n) = o(prime(n)), as n goes to infinity.

%C If the conjecture is true, then A242719(n) ~ prime(n)^2. Indeed, A242719(n) >= prime(n)^2 + 1; on the other hand, by the conjecture, we have A242719(n)/prime(n) <= a(n) + 1 + prime(n) = prime(n)*(1+o(1)).

%H Peter J. C. Moses, <a href="/A246819/b246819.txt">Table of n, a(n) for n = 2..2001</a>

%Y Cf. A242719, A242720, A246748, A246821.

%K nonn

%O 2,4

%A _Vladimir Shevelev_, Sep 04 2014

%E More terms from _Peter J. C. Moses_, Sep 04 2014

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