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a(n) = A246793(A005669(n)).
2

%I #13 Nov 04 2014 22:55:04

%S 1,1,2,3,5,5,7,8,9,8,12,10,11,12,9,12,15,10,11,15,10,17,13,16,20,17,

%T 21,19,19,24,13,23,18,21,17,26,26,29,19,23,23,25,27,27,29,24,26,25,33,

%U 28,32,32,31,36,35,37,42,33,28,35,30,36,30,34,44,29,32,34,33,30,40,38,34,44

%N a(n) = A246793(A005669(n)).

%C This sequence evaluates the largest m's defined in A246793 for the index of primes where largest gaps occurs.

%C Conjecture: For every n, a(n) is positive.

%C a(75) = 44 and A246794(75) = 6 hence A182134(34952141021660495 - k) = k for 5 < k < 45, where 34952141021660495 = A005669(75).

%Y Cf. A000040, A002386, A005669, A182134, A246785, A246794.

%K nonn,hard

%O 2,3

%A _Farideh Firoozbakht_, Oct 24 2014