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A246029
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a(n) = Product_{i in row n of A245562} prime(i).
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6
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1, 2, 2, 3, 2, 4, 3, 5, 2, 4, 4, 6, 3, 6, 5, 7, 2, 4, 4, 6, 4, 8, 6, 10, 3, 6, 6, 9, 5, 10, 7, 11, 2, 4, 4, 6, 4, 8, 6, 10, 4, 8, 8, 12, 6, 12, 10, 14, 3, 6, 6, 9, 6, 12, 9, 15, 5, 10, 10, 15, 7, 14, 11, 13, 2, 4, 4, 6, 4, 8, 6, 10, 4, 8, 8, 12, 6, 12, 10, 14, 4, 8, 8, 12, 8, 16, 12, 20, 6, 12, 12, 18
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OFFSET
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0,2
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COMMENTS
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This is the Run Length Transform of S(n) = {1,2,3,5,7,11,...} (1 followed by the primes).
The Run Length Transform of a sequence {S(n), n>=0} is defined to be the sequence {T(n), n>=0} given by T(n) = Product_i S(i), where i runs through the lengths of runs of 1's in the binary expansion of n. E.g., 19 is 10011 in binary, which has two runs of 1's, of lengths 1 and 2. So T(19) = S(1)*S(2). T(0)=1 (the empty product).
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LINKS
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N. J. A. Sloane, On the No. of ON Cells in Cellular Automata, Video of talk in Doron Zeilberger's Experimental Math Seminar at Rutgers University, Feb. 05 2015: Part 1, Part 2
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FORMULA
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EXAMPLE
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Written as an irregular triangle in which row lengths is A011782:
1;
2;
2,3;
2,4,3,5;
2,4,4,6,3,6,5,7;
2,4,4,6,4,8,6,10,3,6,6,9,5,10,7,11;
2,4,4,6,4,8,6,10,4,8,8,12,6,12,10,14,3,6,6,9,6,12,9,15,5,10,10,15,7,14,11,13;
...
Right border gives the noncomposite numbers. This is simply a restatement of the theorem that this sequence is the Run Length Transform of A008578.
(End)
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MAPLE
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ans:=[];
for n from 0 to 100 do lis:=[]; t1:=convert(n, base, 2); L1:=nops(t1); out1:=1; c:=0;
for i from 1 to L1 do
if out1 = 1 and t1[i] = 1 then out1:=0; c:=c+1;
elif out1 = 0 and t1[i] = 1 then c:=c+1;
elif out1 = 1 and t1[i] = 0 then c:=c;
elif out1 = 0 and t1[i] = 0 then lis:=[c, op(lis)]; out1:=1; c:=0;
fi;
if i = L1 and c>0 then lis:=[c, op(lis)]; fi;
od:
a:=mul(ithprime(i), i in lis);
ans:=[op(ans), a];
od:
ans;
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MATHEMATICA
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f[n_, i_, x_] := f[n, i, x] = Which[n == 0, x, EvenQ[n], f[n/2, i + 1, x], True, f[(n - 1)/2, i, x*Prime[i]]];
a5940[n_] := f[n - 1, 1, 1];
a181819[n_] := Times @@ Prime[FactorInteger[n][[All, 2]]];
a[0] = 1; a[n_] := a181819[a5940[n + 1]];
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PROG
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(Python)
from operator import mul
from functools import reduce
from re import split
from sympy import prime
return reduce(mul, (prime(len(d)) for d in split('0+', bin(n)[2:]) if d != '')) if n > 0 else 1
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CROSSREFS
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Cf. A245562, A000045, A001045, A005940, A008578, A011782, A071053, A181819, A245565, A246028, A253081 (partial sums).
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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