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Permutation of natural numbers: a(n) = A245607(A245708(n)).
7

%I #9 Aug 11 2014 22:22:25

%S 1,2,3,4,5,6,9,8,13,10,7,12,37,18,19,16,69,26,17,20,33,14,277,24,213,

%T 74,11,36,73,38,71,32,45,138,25,52,1109,34,457,40,173,66,43,28,549,

%U 554,3351,48,77,426,21,148,53,22,135,72,125,146,651,76,273,142,55,64

%N Permutation of natural numbers: a(n) = A245607(A245708(n)).

%C The even bisection halved gives the sequence back. The odd bisection incremented by one and halved gives A245711.

%H Antti Karttunen, <a href="/A245705/b245705.txt">Table of n, a(n) for n = 1..10001</a>

%H <a href="/index/Per#IntegerPermutation">Index entries for sequences that are permutations of the natural numbers</a>

%F a(n) = A245607(A245708(n)).

%o (PARI)

%o A245705(n) = A245607(A245708(n));

%o for(n=1, 10001, write("b245705.txt", n, " ", A245705(n)));

%o \\ Other code as in A245607 and A245708.

%o (Scheme) (define (A245705 n) (A245607 (A245708 n)))

%Y Inverse: A245706.

%Y Fixed points: A245709.

%Y Cf. A245607, A245708, A245605, A245711.

%K nonn

%O 1,2

%A _Antti Karttunen_, Jul 30 2014