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%I #5 Nov 16 2016 12:37:14
%S 12,41,268,941,2424,5101,7730,14519,26882,47381,54282,93567,138214,
%T 207081,288862,319535,489922,628893,878082,1128849,1220884,1640461,
%U 1997876,2688937,3290036,3680517,4461044,5245231,6537106,7081377,8727400
%N Number of length 5 0..n arrays with each partial sum starting from the beginning no more than one standard deviation from its mean.
%C Row 5 of A244788
%H R. H. Hardin, <a href="/A244793/b244793.txt">Table of n, a(n) for n = 1..210</a>
%e Some solutions for n=10
%e ..2....3....4....8....7....8....5....3....2....2....6....3....8....4....7....5
%e ..9....3....7....1....3....3....8....7....6....7....0....5....5....9....2....8
%e ..6....6....2....5....2....5....6....8....7....8....9....4....7....2....5....3
%e ..4....6....9....8....9...10....1....0....1....4....5....2....4....3...10....0
%e ..7....9....3....5....0....5....2....1...10....0....0....6....3....7....6....6
%K nonn
%O 1,1
%A _R. H. Hardin_, Jul 06 2014