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A244603
Least number k such that n^k contains the digit n n times.
2
1, 18, 21, 32, 30, 38, 33, 55, 69
OFFSET
1,2
EXAMPLE
2^18 is the first power of 2 to contain 2 twice. So a(2) = 18.
3^21 is the first power of 3 to contain 3 three times. So a(3) = 21.
PROG
(Python)
def tes(n):
for k in range(1, 10**3):
if(str(n**k).count(str(n))) == n:
return k
n = 1
while n < 10:
print(tes(n), end=', ')
n += 1
CROSSREFS
Sequence in context: A001101 A088341 A105145 * A120416 A293751 A090891
KEYWORD
nonn,base,fini,full
AUTHOR
Derek Orr, Jul 01 2014
STATUS
approved