

A243259


Numbers n such that n appears in the sequence x(i) = x(i1) +/ digitsum(x(i1)), where even digitsums are added, odd digitsums are subtracted and x(0) = n.


2



99, 108, 117, 198, 207, 216, 297, 306, 315, 396, 405, 414, 495, 504, 513, 594, 603, 612, 693, 702, 711, 792, 801, 810, 972, 990, 999, 1008, 1098, 1107, 1116, 1197, 1206, 1215, 1296, 1305, 1314, 1395, 1404, 1413, 1494, 1503, 1512, 1593, 1602, 1611, 1692, 1701
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OFFSET

1,1


COMMENTS

The sequence begins with x(0) = n and continues by adding or subtracting the digitsum. When the digitsum(x(i1)) is even, x(i) = x(i1) + digitsum(x(i1)), otherwise x(i) = x(i1)  digitsum(x(i1)).


LINKS

Anthony Sand, Table of n, a(n) for n = 1..1000


FORMULA

x(i) = x(i1) + digitsum(x(i1)) * (1  (digitsum(x(i1)) mod 2) * 2).


EXAMPLE

digitsum(99) = 18, 18 is even, so 99 + 18 = 117. digitsum(117) = 9, 9 is odd, so 177  9 = 108. 108  9 = 99, hence 99 belongs to sequence.
108  9 = 99, 99 + 18 = 117, 117  9 = 108, hence 108 is in the sequence.
117  9 = 108. 108  9 = 99. 99 + 18 = 117.
198 + 18 = 216. 216  9 = 207. 207  9 = 198.


CROSSREFS

Cf. A004207, A243260.
Sequence in context: A213157 A317592 A296881 * A171904 A171903 A072433
Adjacent sequences: A243256 A243257 A243258 * A243260 A243261 A243262


KEYWORD

nonn,base


AUTHOR

Anthony Sand, Jun 02 2014


STATUS

approved



