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%I #5 May 30 2014 01:04:27
%S 0,1,3,6,8,12,13,14,15,18,20,24,28,30,31,32,36,38,39,40,42,44,48,54,
%T 56,57,60,62,63,68,72,74,78,80,84,90,91,93,96,98,102,104,108,110,112,
%U 114,120,121,124,126,127,128,132,133,138,140,144,150,152,156,158
%N Possible values of A242962 in increasing order.
%C A242962(n) = (n*(n+1)/2) mod antisigma(n) = A000217(n) mod A024816(n); where A000217(n) = triangular numbers, A024816(n) = sum of numbers less than n which do not divide n.
%C Complement of A243118.
%C a(n) = A002191(n+1) for n >= 5; where A002191 = possible values of sigma(n).
%e 0 is in the sequence because there is a number m such that A242962(m) = 0; m = 3.
%Y Cf. A000203, A002191, A242962, A242963, A243118.
%K nonn
%O 1,3
%A _Jaroslav Krizek_, May 29 2014
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