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A243076
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Let f(p,i) = smallest prime m >= p such that m == i (mod p); a(n) = Sum_{i=0..p-1} f(p,i), where p = n-th prime.
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1
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5, 15, 55, 119, 341, 533, 901, 1387, 1909, 3103, 4061, 5365, 6601, 7783, 9635, 12455, 16343, 17507, 20033, 24069, 27083, 29941, 33283, 42453, 47433, 53631, 54693, 60241, 66163, 69721, 86741, 92879, 104805, 102443, 126203, 130011, 136119, 143603, 157147
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OFFSET
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1,1
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COMMENTS
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a(n) is always odd.
Obviously, prime(n)|a(n) for n>1.
a(n)/prime(n), n>1: 5, 11, 17, 31, 41, 53, 73, 83, 107, 131, 145, 161, 181, 205, 235, 277, 287, 299, 339, etc.
Values of n such that a(n) < a(n-1): 34, 51, 57, 58, 65, 69, 71, 91, 96, 105, 109, 111, ....
(End)
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LINKS
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EXAMPLE
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a(1) = 5 = 2+3,
a(2) = 15 = 3+7+5,
a(3) = 55 = 5+11+7+13+19,
a(4) = 119 = 7+29+23+17+11+19+13,
a(5) = 341 = 11+23+13+47+37+71+17+29+19+31+43, etc.
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MATHEMATICA
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f[n_] := Block[{p = Prime@ n, q, i = s = 0}, While[i < p, q = If[OddQ@ i, 2, 1]*p + i; While[ !PrimeQ@ q, q += 2p]; s += q; i++]; s]; f[1] = 5; Array[f, 100] (* Robert G. Wilson v, Jun 21 2017 *)
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PROG
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(PARI) a(n) = {res = 0; for (index = 0, prime(n)-1, m = n; while ((prime(m) % prime(n)) != index, m++; ); res += prime(m); ); res; } \\ Michel Marcus, Jun 04 2014
(Python)
from sympy import prime, isprime
def a(n):
if n==1: return 5
p=prime(n)
i=0
s=0
while i<p:
q=(2 if i%2 else 1)*p + i
while not isprime(q): q+=2*p
s+=q
i+=1
return s
print([a(n) for n in range(1, 101)]) # Indranil Ghosh, Jun 22 2017, after Mathematica code
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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