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Number of cyclic arrangements (up to direction) of {0,1,...,n-1} such that the sum of any two neighbors is a prime.
20

%I #12 Oct 19 2018 16:58:53

%S 0,0,0,0,1,1,2,6,6,22,80,504,840,6048,3888,37524,72976,961776,661016,

%T 11533030,7544366,133552142,208815294,5469236592,6429567323,

%U 153819905698,182409170334,4874589558919,7508950009102,209534365631599

%N Number of cyclic arrangements (up to direction) of {0,1,...,n-1} such that the sum of any two neighbors is a prime.

%C a(n)=NPC(n;S;P) is the count of all neighbor-property cycles for a specific set S={0,1,...,n-1} of n elements and a specific pair-property P. For more details, see the link and A242519.

%C For the same pair-property P but the set {1 through n}, see A051252. Using for pair-property the difference, rather than the sum, one obtains A228626.

%H S. Sykora, <a href="http://dx.doi.org/10.3247/SL5Math14.002">On Neighbor-Property Cycles</a>, <a href="http://ebyte.it/library/Library.html#math">Stan's Library</a>, Volume V, 2014.

%e The first such cycle is of length n=5: {0,2,1,4,3}.

%e The first case with 2 solutions is for cycle length n=7:

%e C_1={0,2,3,4,1,6,5}, C_2={0,2,5,6,1,4,3}.

%e The first and the last of the 22 such cycles of length n=10 are:

%e C_1={0,3,2,1,4,9,8,5,6,7}, C_22={0,5,8,9,4,3,2,1,6,7}.

%t A242527[n_] := Count[Map[lpf, Map[j0f, Permutations[Range[n - 1]]]], 0]/2;

%t j0f[x_] := Join[{0}, x, {0}];

%t lpf[x_] := Length[Select[asf[x], ! PrimeQ[#] &]];

%t asf[x_] := Module[{i}, Table[x[[i]] + x[[i + 1]], {i, Length[x] - 1}]];

%t Table[A242527[n], {n, 1, 10}]

%t (* OR, a less simple, but more efficient implementation. *)

%t A242527[n_, perm_, remain_] := Module[{opt, lr, i, new},

%t If[remain == {},

%t If[PrimeQ[First[perm] + Last[perm]], ct++];

%t Return[ct],

%t opt = remain; lr = Length[remain];

%t For[i = 1, i <= lr, i++,

%t new = First[opt]; opt = Rest[opt];

%t If[! PrimeQ[Last[perm] + new], Continue[]];

%t A242527[n, Join[perm, {new}],

%t Complement[Range[n - 1], perm, {new}]];

%t ];

%t Return[ct];

%t ];

%t ];

%t Table[ct = 0; A242527[n, {0}, Range[n - 1]]/2, {n, 1, 15}]

%t (* _Robert Price_, Oct 18 2018 *)

%o (C++) See the link.

%Y Cf. A051252, A228626, A242519, A242520, A242521, A242522, A242523, A242524, A242525, A242526, A242528, A242529, A242530, A242531, A242532, A242533, A242534.

%K nonn,hard

%O 1,7

%A _Stanislav Sykora_, May 30 2014

%E a(23)-a(30) from _Max Alekseyev_, Jul 09 2014