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A240905
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Smallest k such that the minimal factor in factorization of k! over distinct terms of A050376 is A050376(n), or a(n)=0 if there is no such k.
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7
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2, 12, 20, 6, 10, 130, 180, 240, 480, 597, 901, 40537, 15841, 23401, 36720, 112321, 20377, 177842
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OFFSET
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1,1
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COMMENTS
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a(n) is the smallest k such that the minimal infinitary divisor of k! is A050376(n).
Conjecture. All a(n)>0.
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LINKS
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EXAMPLE
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Let n=4. A050376(4)=5. For k=2,3,4,5,6, we have the following factorizations over distinct terms of A050376: 2!=2,3!=2*3,4!=2*3*4,5!=2*3*4*5,6!=5*9*16. Only the last factorization begins with 5. So a(4)=6.
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CROSSREFS
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Cf. A240537, A240606, A240619, A240620, A240668, A240669, A240670, A240672, A240695, A240751, A240755, A240764.
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KEYWORD
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nonn,more
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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