

A238606


Array: t(n,k) = number of partitions p of n such that the principal antidiagonal of the Ferrers matrix of p has k 1's.


1



1, 2, 2, 1, 4, 1, 4, 3, 8, 2, 1, 10, 3, 2, 14, 7, 1, 20, 5, 5, 30, 5, 6, 1, 36, 15, 2, 3, 52, 16, 6, 3, 70, 13, 15, 3, 94, 22, 12, 7, 122, 32, 8, 13, 1, 160, 45, 12, 10, 4, 206, 51, 26, 8, 6, 276, 49, 44, 9, 7, 350, 75, 30, 28, 7, 448, 108, 22, 38, 11, 566
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OFFSET

1,2


COMMENTS

"Ferrers matrix" is defined (A237981) as follows: an m X m matrix (x(i,j)) of 0s and 1s satisfying three properties: (1) x(1,m) = 1 or x(m,1) = 1; (2) x(i,j+1) >= x(i,j) for j=1..m1 and i = 1..m; and (3) x(i+1,j) >= x(i,j) for i=1..m1 and j=1..m. Ferrers matrices arise from Ferrers graphs of partitions, as follows: suppose that p is a partition of n, and let m = max{greatest part of p, number of parts of p}. Write the Ferrers graph of p with 1s as nodes, and pad the graph with 0s to form an mXm square matrix, which is the Ferrers matrix of p.
If "antidiagonal" is changed to "diagonal" in the definition of t(n,k), the resulting array is given by A115995. For both arrays, the sum of terms in row n is A000041(n).


LINKS

Table of n, a(n) for n=1..71.
Clark Kimberling and Peter J. C. Moses, Ferrers Matrices and Related Partitions of Integers


EXAMPLE

First 17 rows:
1
2
2 .... 1
4 .... 1
4 .... 3
8 .... 2 .... 1
10 ... 3 .... 2
14 ... 7 .... 1
20 ... 5 .... 5
30 ... 5 .... 6 ... 1
36 ... 15 ... 2 ... 3
52 ... 16 ... 6 ... 3
70 ... 13 ... 15 .. 3
94 ... 22 ... 12 .. 7
122 ... 32 .. 8 ... 13 .. 1
160 ... 45 .. 12 .. 10 .. 4
Row 5 counts 4 antidiagonals that have exactly one 1 and 3 antidiagonals that have exactly two 1's. The Ferrers matrix for each of the latter three cases are as shown below.
For the partition 32:
1 1 1
1 1 0
0 0 0 (antidiagonal, from row 1: 1,1,0)
For the partition 311:
1 1 1
1 0 0
1 0 0 (antidiagonal, from row 1: 1,0,1,)
For the partition 221:
1 1 0
1 1 0
1 0 0 (antidiagonal, from row 1: 0,1,1)


MATHEMATICA

z = 30; ferrersMatrix[list_] := PadRight[Map[Table[1, {#}] &, #], {#, #} &[Max[#, Length[#]]]] &[list]; diagAntidiagDots[list_] := {Total[Diagonal[#]], Total[Diagonal[Reverse[#]]]} &[ferrersMatrix[list]]; u[n_, k_] := Length[Select[ Map[diagAntidiagDots, IntegerPartitions[n]], #[[2]] == k &]]; t[n_] := t[n] = Floor[(1 + Sqrt[1 + 8 n])/2]; w = Table[u[n, k], {n, 1, z}, {k, 1, t[n]}]; y = Flatten[w] (* A238606 *) (* Peter J. C. Moses, Mar 01 2014 *)


CROSSREFS

Cf. A115994, A000041.
Sequence in context: A002126 A129721 A268193 * A054995 A018219 A174714
Adjacent sequences: A238603 A238604 A238605 * A238607 A238608 A238609


KEYWORD

nonn,tabf,easy


AUTHOR

Clark Kimberling, Mar 01 2014


STATUS

approved



