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A236417
a(n) = |{0 < k < n: p = phi(k)/2 + phi(n-k)/12 + 1 and A047967(p) are both prime}|.
5
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 2, 0, 0, 2, 1, 0, 1, 0, 3, 1, 0, 1, 1, 1, 2, 1, 2, 0, 1, 2, 2, 2, 1, 2, 1, 1, 3, 1, 1, 4, 2, 0, 1, 3, 2, 2, 0, 2, 2, 4, 2, 3, 0, 3, 2
OFFSET
1,56
COMMENTS
Conjecture: a(n) > 0 for all n > 98.
We have verified this for n up to 36000.
The conjecture implies that there are infinitely many primes p with A047967(p) prime.
LINKS
EXAMPLE
a(36) = 1 since phi(23)/2 + phi(13)/12 + 1 = 13 with A047967(13) = 83 prime.
a(71) = 1 since phi(43)/2 + phi(28)/12 + 1 = 23 with A047967(23) = 1151 prime.
MATHEMATICA
pq[n_]:=PrimeQ[n]&&PrimeQ[PartitionsP[n]-PartitionsQ[n]]
f[n_, k_]:=EulerPhi[k]/2+EulerPhi[n-k]/12+1
a[n_]:=Sum[If[pq[f[n, k]], 1, 0], {k, 1, n-1}]
Table[a[n], {n, 1, 100}]
CROSSREFS
KEYWORD
nonn
AUTHOR
Zhi-Wei Sun, Jan 25 2014
STATUS
approved