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A236363
Sum of digits of A114440(n).
2
1, 2, 3, 4, 5, 6, 7, 8, 9, 3, 9, 3, 6, 9, 9, 6, 9, 12, 9, 9, 9, 9, 12, 9, 9, 9, 9, 9, 18, 9, 9, 18, 18, 18, 18, 18, 18, 18, 18, 18, 9, 18, 18, 18, 18, 27, 18, 9, 18, 18, 27, 18, 18, 27, 27, 27, 18, 36, 27, 27, 27, 18, 27, 27, 27, 27, 27, 27, 27, 27, 27, 36, 36, 36, 36, 27
OFFSET
1,2
COMMENTS
Because A114440 is finite, this sequence is necessarily also finite.
Note that after a(23), all terms are divisible by 9 since all the terms that take three steps to arrive at 1 are multiples of 9 so the sum of digits of their predecessors must also be a multiple of 9.
LINKS
FORMULA
a(n) = A007953(A114440(n)).
CROSSREFS
KEYWORD
nonn,base,fini,full
AUTHOR
Ray Chandler, Jan 23 2014
STATUS
approved