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A235725 Values k(i) such that k(i) + k(i+3) = k(i+1) + k(i+2), where k(i) is A022885(i). 1
5, 353, 541, 853, 2341, 4217, 4229, 8219, 10663, 11047, 13591, 18593, 21577, 28387, 30181, 34457, 37853, 52021, 55333, 57203, 75389, 84431, 93229, 110603, 120811, 147451, 153499, 162907, 166357, 176797, 179581, 219953, 243671, 246203, 307253, 342037, 359701 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,1
LINKS
EXAMPLE
Four consecutive Kimberling primes(A022885), beginning with 5 are 5,7,11,13. Since 5+13 = 7+11, then 5 is in the sequence; four consecutive Kimberling primes, beginning with 7 are 7,11,13,23. Since 7+23 is not equal to 11+13, then 7 is not in the sequence.
MATHEMATICA
Nest[Map[#[[1]]&, Select[Partition[#, 4, 1], #[[1]]+#[[4]]==#[[2]]+#[[3]]&]]&, Prime[Range[5000]], 2]
PROG
(PARI) isA022885(p) = {my(k = primepi(p)); (p == prime(k)) && ((prime(k) + prime(k+3)) == (prime(k+1) + prime(k+2))); }
lista(nn) = {prm = primes(nn); vkp = select(p->isA022885(p), prm); for(n=1, #vkp-3, if ((vkp[n] + vkp[n+3]) == (vkp[n+1] + vkp[n+2]), print1(vkp[n], ", ")); ); } \\ Michel Marcus, Jan 15 2014
CROSSREFS
Cf. A022885.
Sequence in context: A193806 A158105 A203527 * A332135 A225578 A172014
KEYWORD
nonn
AUTHOR
Vladimir Shevelev, Jan 15 2014
EXTENSIONS
a(5)-a(37) from Giovanni Resta, Jan 15 2014
STATUS
approved

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Last modified April 19 19:02 EDT 2024. Contains 371798 sequences. (Running on oeis4.)