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A233700
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Decimal expansion of 1/sin(arctan(1/t)) or t/sin(arctan(t)) where t = 2*Pi: hypotenuse for a right triangle of equal area to a disk.
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1
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6, 3, 6, 2, 2, 6, 5, 1, 3, 1, 5, 6, 7, 3, 2, 8, 3, 9, 3, 6, 9, 1, 2, 4, 5, 4, 4, 0, 5, 8, 6, 8, 0, 4, 4, 1, 0, 6, 9, 9, 7, 1, 4, 9, 8, 5, 1, 3, 8, 9, 8, 9, 6, 8, 6, 5, 8, 2, 0, 4, 1, 6, 1, 7, 0, 4, 5, 9, 9, 8, 5, 8, 7, 3, 3, 1, 7, 8, 4, 8, 5, 4, 1, 3, 4, 5, 5, 0, 8, 7, 7, 1, 3
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OFFSET
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1,1
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COMMENTS
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"The great mathematician Archimedes used the tools of Euclidean geometry to show that the area inside a circle is equal to that of a right triangle whose base has the length of the circle's circumference and whose height equals the circle's radius in his book Measurement of a Circle." (Quote from Wikipedia link)
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LINKS
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FORMULA
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EXAMPLE
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6.362265131567328393691245440586804410699714985138989686582041617045998587331...
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MATHEMATICA
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RealDigits[(2*Pi)/Sin[ArcTan[2*Pi]], 10, 120][[1]] (* Harvey P. Dale, Jul 12 2014 *)
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PROG
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(PARI) sqrt(1+(2*Pi)^2)
(Magma) C<i> := ComplexField(); Sqrt(1 + 4*Pi(C)^2) // G. C. Greubel, Jan 08 2018
(Magma) R:=RealField(110); SetDefaultRealField(R); n:=Sqrt(1+4*Pi(R)^2); Reverse(Intseq(Floor(10^108*n))); // Bruno Berselli, Mar 13 2018
(Julia)
using Nemo
RR = RealField(310)
t = const_pi(RR) + const_pi(RR)
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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