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A233551 Numbers m congruent to 5 mod 6 such that for all k >= 1 the numbers (m*4^k + 1)/3 are composite. 2
419, 659, 1769, 2609, 2651, 2981 (list; graph; refs; listen; history; text; internal format)
OFFSET

1,1

COMMENTS

The next term may or may not be 3719.

Comment from Hugo Pfoertner, May 28 2019: At the moment, the sequence is confirmed for all terms < 3719. So far, it is not known whether (3719*4^k+1)/3 is composite for all k > 50000.

Updates from Hugo Pfoertner, Jun 05 2019 and Jun 24 2019: All numbers marked with ? in the list  below are checked through k <= 200000. No other numbers with unknown status exist below 25000.

The sequence may continue as follows: 3719?, 4889, 5459?, 5561, 5771, 6341, 6509, 7271, 7829, 8609, 9959, 10019?, 10289?, 10799, 10841, 11171, 11429, 12809?, 13079, 13751, 13961, 14279?, 14531, 14699, 15419?, 15461, 16019, 16799, 18149, 18971?, 18989, 19031, 19361, 20261?, 21269, 21941, 22151, 22529?, 22721, 22889, 23099?, 23651, 24209, 24989

LINKS

Table of n, a(n) for n=1..6.

G. L. Honaker, Jr. and Chris Caldwell, Prime Curios! 419

EXAMPLE

419 is in the sequence. Consider (419*4^m+1)/3: for m == 0 (mod 6) it is divisible by 5 and 7, for m == 1 (mod 6) divisible by 13, for m == 2 (mod 6) divisible by 3 and 5, for m == 3 (mod 6) divisible by 7, for m == 4 (mod 6) divisible by 5 and for m == 5 (mod 6) divisible by 3. The "mod 6" is derived from the fact that 4^6-1 = 3^2*5*7*13, so 4^6 == 1 (mod 5), 4^6 == 1 (mod 7), 4^6 = 1 (mod 9) and 4^6 == 1 (mod 13). - Andrew Weimholt, May 26 2019

6971 is not in the sequence, because (6971*4^204688+1)/3 is a prime with 123238 decimal digits. - Hugo Pfoertner, Jun 05 2019

CROSSREFS

Cf. A308177.

Sequence in context: A138062 A350781 A097233 * A142281 A242281 A142733

Adjacent sequences:  A233548 A233549 A233550 * A233552 A233553 A233554

KEYWORD

nonn,more

AUTHOR

Arkadiusz Wesolowski, Dec 12 2013

EXTENSIONS

Edited by N. J. A. Sloane, May 28 2019

STATUS

approved

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Last modified January 26 22:05 EST 2022. Contains 350601 sequences. (Running on oeis4.)