1,1

Donovan Johnson, Table of n, a(n) for n = 1..10000

For n=12, the two solutions are: 999999999896 and 999999999905, for which we have A062028(999999999896) = A062028(999999999905) = 10^12.

Cf. A062028, A232489, A232490, A232491.

Sequence in context: A001704 A127421 A112131 * A088997 A049852 A045532

Adjacent sequences: A233029 A233030 A233031 * A233033 A233034 A233035

nonn,base

Max Alekseyev, Dec 03 2013

approved