
COMMENTS

a(n) = least k such that A232096(k) >= n.
Each A000217(a(n)) is divisible by A118381(n).
Each a(n) or a(n)+1 is divisible by 2*A060818(n) = A086117(n+1).
Each a(n) or a(n)+1 is divisible by A060828(n), and similarly for all the higher bases.
If we were instead searching for the first occurrence where A232096 gets a new distinct value, then we would have another sequence, b, which would start as: 1, 3, 4, 15, 32, 224, 575, 4095, ... as those distinct values do not appear in monotone order, being for n>=1, A232096(b(n)) = 1, 3, 2, 5, 4, 7, 6, 8, 9, 10, ...
