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A231003 Number of years after which it is not possible to have a date falling on the same day of the week, in the Julian calendar. 1

%I #4 Nov 02 2013 23:39:30

%S 1,2,3,4,7,8,9,10,12,13,14,15,16,18,19,20,21,24,25,26,27,29,30,31,32,

%T 35,36,37,38,40,41,42,43,44,46,47,48,49,52,53,54,55,57,58,59,60,63,64,

%U 65,66,68,69,70,71,72,74,75,76,77,80,81,82,83,85,86,87,88,91,92,93,94,96,97

%N Number of years after which it is not possible to have a date falling on the same day of the week, in the Julian calendar.

%C In the Julian calendar, a year is a leap year if and only if it is a multiple of 4 and all century years are leap years.

%C Assuming this fact, this sequence is periodic with a period of 28.

%C This is the complement of A231000.

%H Time And Date, <a href="http://www.timeanddate.com/calendar/repeating.html">Repeating Calendar</a>

%H Time And Date, <a href="http://www.timeanddate.com/calendar/julian-calendar.html">Julian Calendar</a>

%o (PARI) for(i=0,420,j=0;for(y=0,420,if(((5*(y\4)+(y%4))%7)==((5*((y+i)\4)+((y+i)%4))%7),j=1));if(j==0,print1(i", ")))

%Y Cf. A230995-A231014.

%Y Cf. A230998 (Gregorian calendar).

%K nonn,easy

%O 1,2

%A _Aswini Vaidyanathan_, Nov 02 2013

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