login
A230432
Simple self-inverse permutation of natural numbers: after zero, list each block of A219661(n) numbers in reverse order, from A226061(n+1) to A219665(n).
6
0, 1, 3, 2, 8, 7, 6, 5, 4, 27, 26, 25, 24, 23, 22, 21, 20, 19, 18, 17, 16, 15, 14, 13, 12, 11, 10, 9, 110, 109, 108, 107, 106, 105, 104, 103, 102, 101, 100, 99, 98, 97, 96, 95, 94, 93, 92, 91, 90, 89, 88, 87, 86, 85, 84, 83, 82, 81, 80, 79, 78, 77, 76, 75, 74, 73
OFFSET
0,3
COMMENTS
This permutation can be used to map between the sequences A219666 and A230416. E.g. A219666(n) = A230416(a(n)) and vice versa: A230416(n) = A219666(a(n)).
FORMULA
a(n) = A219665(A230411(n+1)) - A230431(n) - 1.
PROG
(Scheme)
(define (A230432 n) (if (zero? n) n (- (A219665 (A230411 (+ 1 n))) (A230431 n) 1)))
CROSSREFS
Analogous sequence for binary system: A218602.
Sequence in context: A122339 A057163 A130918 * A195305 A327575 A328645
KEYWORD
nonn
AUTHOR
Antti Karttunen, Oct 22 2013
STATUS
approved