



0, 1, 2, 1, 3, 3, 1, 2, 4, 5, 4, 5, 1, 2, 3, 3, 5, 7, 7, 8, 5, 7, 7, 8, 1, 2, 3, 3, 4, 5, 4, 5, 6, 9, 10, 11, 9, 12, 11, 13, 6, 9, 10, 11, 9, 12, 11, 13, 1, 2, 3, 3, 4, 5, 4, 5, 5, 7, 7, 8, 5, 7, 7, 8, 7, 11, 13, 14, 13, 17, 15, 18, 11, 16, 17, 19, 14
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OFFSET

0,3


COMMENTS

From Yosu Yurramendi, Jun 30 2014: (Start)
If the terms (n>0) are written as an array (leftaligned fashion):
1,
2,1,
3,3, 1, 2,
4,5, 4, 5,1, 2, 3, 3,
5,7, 7, 8,5, 7, 7, 8,1,2, 3, 3,4, 5, 4, 5,
6,9,10,11,9,12,11,13,6,9,10,11,9,12,11,13,1,2,3,3,4,5,4,5,5,7,7,8,5,7,7,8,
then the sum of the kth row is 3^(k1) and each column is an arithmetic sequence. The differences of the arithmetic sequences gives the sequence A071585 (a(2^(p+1)+k)  a(2^p+k) = A071585(k), p = 0,1,2,..., k = 0,1,2,...,2^p1).
The first terms of each column give A071766. The second terms of each column give A086593. So, A086593(n) = A071585(n) + A071766(n).
If the rows (n>0) are written in a rightaligned fashion:
1,
2,1,
3,3,1,2,
4,5,4,5,1,2,3,3,
5,7,7,8,5,7,7,8,1,2,3,3,4,5,4,5,
6,9,10,11,9,12,11,13,6,9,10,11,9,12,11,13,1,2,3,3,4,5,4,5,5,7,7,8,5,7,7,8,
then each column is a Fibonacci sequence (a(2^(p+2)+k) = a(2^(p+1)+k) + a(2^p+k) p = 0,1,2,..., k = 0,1,2,...,2^p1, with a_k(1) = A071585(k) and a_k(2) = A071766(k) being the first two terms of each column sequence).


LINKS

Table of n, a(n) for n=0..76.
Index entries for fraction trees


EXAMPLE

A229742/A071766 = 0, 1, 2, 1/2, 3, 3/2, 1/3, 2/3, 4, 5/2, 4/3, 5/3, 1/4, 2/5, 3/4, 3/5, 5, 7/2, 7/3, 8/3, 5/4, 7/5, 7/4, 8/5, ... (this is the HCS form of the SternBrocot tree).


PROG

(R)
blocklevel < 6 # arbitrary
a < 1
for(m in 0:blocklevel) for(k in 0:(2^(m1)1)){
a[2^(m+1)+k] < a[2^m+k] + a[2^m+2^(m1)+k]
a[2^(m+1)+2^(m1)+k] < a[2^(m+1)+k]
a[2^(m+1)+2^m+k] < a[2^m+2^(m1)+k]
a[2^(m+1)+2^m+2^(m1)+k] < a[2^m+k]
}
a
# Yosu Yurramendi, Jul 11 2014


CROSSREFS

Cf. A071585, A071766, A086593.
Sequence in context: A110569 A140815 A134840 * A126572 A162910 A098975
Adjacent sequences: A229739 A229740 A229741 * A229743 A229744 A229745


KEYWORD

nonn,frac


AUTHOR

N. J. A. Sloane, Oct 05 2013, at the suggestion of Kevin Ryde.


STATUS

approved



