%N Numbers k such that there is a m with 2^m/(m+1) < binomial(m,k) <= 2^m/m and k < m/2.
%H T. D. Noe, <a href="/A229486/b229486.txt">Table of n, a(n) for n = 1..104</a> (for m less than 10^5)
%Y Cf. A229484.
%A _T. D. Noe_, Oct 04 2013