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Numbers m such that there is a k with 2^m/(m+1) < binomial(m,k) <= 2^m/m and k < m/2.
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%I #4 Oct 04 2013 15:36:39

%S 2,4,19,61,89,130,139,291,343,521,712,788,929,950,971,1080,1289,1387,

%T 1593,1728,1925,1954,2254,2508,2842,3087,3681,4198,4239,4405,4489,

%U 4876,4964,5142,5187,5553,5835,6368,7129,7604,8038,8093,8881,9762,10494,11898

%N Numbers m such that there is a k with 2^m/(m+1) < binomial(m,k) <= 2^m/m and k < m/2.

%H T. D. Noe, <a href="/A229485/b229485.txt">Table of n, a(n) for n = 1..104</a> (terms less than 10^5)

%Y Cf. A229484.

%K nonn

%O 1,1

%A _T. D. Noe_, Oct 04 2013