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A229031
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Number of 5-colorings of the strong product of the complete graph K2 and the cycle graph Cn.
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1
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120, 0, 2400, 3840, 63360, 215040, 1943040, 9031680, 64665600, 346030080, 2243911680, 12792299520, 79437987840, 465890181120, 2838290104320, 16857940623360, 101834835886080, 608260231004160, 3660556491816960, 21919358464819200, 131692072607416320, 789448748118835200, 4739507238312345600, 28425784430470103040
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OFFSET
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2,1
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COMMENTS
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The strong product of K2 and Cn can be regarded as the King's graph on a 2*n cylindrical (or equivalently toroidal) chessboard.
The Kneser graph construction of the Petersen graph relates this to the number of closed walks on the Petersen graph.
More generally, the number of c-colorings of the strong product of Km and Cn is equal to (m!)^n * (c choose m) * (number of closed walks of length n on K(c,m)).
If n is prime then a(n) is divisible by n, since the cyclic group of order n acts on the colorings, partitioning them into orbits of size n. More generally, n divides a(n) for any Carmichael number n, due to the closed form.
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LINKS
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FORMULA
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a(n) = 6^n + 4*(-4)^n + 5*2^n.
a(n) = 4*a(n-1)+20*a(n-2)-48*a(n-3). G.f.: -120*x^2*(4*x-1) / ((2*x-1)*(4*x+1)*(6*x-1)). - Colin Barker, Oct 20 2013
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EXAMPLE
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For n = 2, the graph is the complete graph K4, which has a(4) = 120 different 5-colorings corresponding to ordered 4-subsets of {1,2,3,4,5}.
For n = 3, the graph is the complete graph K6, which cannot be 5-colored, so a(3) = 0. Equivalently, there are no closed walks of length 3 on the Petersen graph.
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MATHEMATICA
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Table[2^n(3^n+4(-2)^n+5), {n, 2, 25}]
LinearRecurrence[{4, 20, -48}, {120, 0, 2400}, 24] (* or *) Drop[CoefficientList[Series[-120*x^2*(4*x - 1) / ((2*x - 1) * (4*x + 1) * (6*x - 1)), {x, 0, 25}], x], 2] (* Indranil Ghosh, Mar 03 2017 *)
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PROG
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(PARI) a(n) = (2^n) * (3^n + 4*(-2)^n + 5) \\ Indranil Ghosh, Mar 03 2017
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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