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A228530
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Summarize the previous two terms!
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1
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1, 11, 31, 3113, 3133, 3153, 215315, 31123335, 41225335, 3132631435, 313263243516, 413283242536, 31527334253618, 3152733435261728, 4152832445263728, 3172634445263738, 2162636435363738, 2142934425663728, 216273442566272819, 319233542556372829
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OFFSET
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1,2
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COMMENTS
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a(k) is found by counting the frequency of the digits in terms a(k-1) and a(k-2). Digits with zero frequency are not counted.
At n=54 the sequence enters a cycle of 46 terms so that for n>=100 we have a(k) = a(k-46)]. [Lars Blomberg, Jan 04 2014]
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LINKS
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EXAMPLE
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For n=5, a(5) is found by counting the frequency of the digits in the last two terms; there are three 1s and three 3s, so you get "three one three three", or 3133.
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CROSSREFS
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Like A005151, but uses the previous two terms instead of just the previous term.
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KEYWORD
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nonn,base
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AUTHOR
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EXTENSIONS
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Corrected a(8)-a(15), added a(16)-a(20) by Lars Blomberg, Jan 04 2014
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STATUS
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approved
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