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 A228483 a(n) = 2 - mu(n), where mu(n) is the Moebius function (A008683). 3
 1, 3, 3, 2, 3, 1, 3, 2, 2, 1, 3, 2, 3, 1, 1, 2, 3, 2, 3, 2, 1, 1, 3, 2, 2, 1, 2, 2, 3, 3, 3, 2, 1, 1, 1, 2, 3, 1, 1, 2, 3, 3, 3, 2, 2, 1, 3, 2, 2, 2, 1, 2, 3, 2, 1, 2, 1, 1, 3, 2, 3, 1, 2, 2, 1, 3, 3, 2, 1, 3, 3, 2, 3, 1, 2, 2, 1, 3, 3, 2, 2, 1, 3, 2, 1, 1, 1 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,2 COMMENTS 1 <= a(n) <= 3: a(n) = 1 when n is both squarefree and has an even number of distinct prime factors (or if n = 1). So a(n) = 1 when mu(n) = 1. a(n) = 2 when n is square-full. a(n) = 3 when n is both squarefree and has an odd number of distinct prime factors. When n is semiprime, a(n) is equal to the ratio of the number of prime factors of n (with multiplicity) to the number of its distinct prime factors. Analogously, when n is semiprime, a(n) is equal to the ratio of the sum of the prime factors of n (with repetition) to the sum of its distinct prime factors. LINKS Vincenzo Librandi, Table of n, a(n) for n = 1..1000 FORMULA a(n) = 2 - mu(n) = 2 - A008683(n). a(A001358(n)) = 5 - tau(A001358(n)) = 3 - omega(A001358(n)) = 3 + 2*A001358(n) - sigma(A001358(n)) - phi(A001358(n)) = Omega(A001358(n))/omega(A001358(n))= sopfr(A001358(n))/sopf(A001358(n)). EXAMPLE a(19) = 3 because mu(19) = -1 and 2 - (-1) = 3. a(20) = 2 because mu(20) = 0 and 2 - 0 = 2. a(21) = 1 because mu(21) = 1 and 2 - 1 = 1. MAPLE with(numtheory); seq(2-mobius(k), k=1..70); MATHEMATICA 2 - MoebiusMu[Range] (* Alonso del Arte, Aug 22 2013 *) PROG (MAGMA) [2-MoebiusMu(n): n in [1..100]]; // Vincenzo Librandi, Aug 23 2013 (PARI) a(n) = 2 - moebius(n); \\ Michel Marcus, Apr 26 2016 CROSSREFS Cf. A001414, A008472, A008683. Sequence in context: A210851 A120992 A129979 * A274709 A260896 A237347 Adjacent sequences:  A228480 A228481 A228482 * A228484 A228485 A228486 KEYWORD nonn,easy AUTHOR Wesley Ivan Hurt, Aug 22 2013 STATUS approved

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Last modified July 21 19:25 EDT 2019. Contains 325199 sequences. (Running on oeis4.)