OFFSET
0,2
COMMENTS
Conjecture: a(n)/24^n is always a positive integer. Similarly, if b(n) denotes the (n+1) X (n+1) Hankel-type determinant with (i,j)-entry equal to A005258(i+j) for all i,j = 0,...,n, then b(n)/10^n is always a positive integer; also, if p is a prime with floor(p/10) odd and p is not congruent to 31 or 39 modulo 40, then p divides b((p-1)/2).
Conjecture: if A(x) = 1 + 48*x + 161856*x^2 + ... denotes the o.g.f. then A(x/3)^(1/8) has integer coefficients (checked up to x^30). - Peter Bala, Apr 22 2018
EXAMPLE
a(0) = 1 since A005259(0+0) = 1.
A(x/3)^(1/8) = 1 + 2*x + 2234*x^2 + 180536476*x^3 + 1041213553880806*x^4 + 431806318205326490858140*x^5 + 12890648790962619413782473229673892*x^6 + 27715196341006992690056202634389754569453086008*x^7 + 4292939920556011562306504817069205738464230629574745210785030*x^8 + 47915532217380103151430239883031701095737468980424637791531495548671526291244*x^9 + .... - Peter Bala, Apr 22 2018
MATHEMATICA
A[n_]:=Sum[Binomial[n, k]^2*Binomial[n+k, k]^2, {k, 0, n}]; a[n_]:=Det[Table[A[i+j], {i, 0, n}, {j, 0, n}]]; Table[a[n], {n, 0, 10}]
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Zhi-Wei Sun, Aug 14 2013
STATUS
approved