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%I #8 Jul 10 2013 02:33:11
%S 2,2,3,3,1,2,3,3,2,5,4,3,3,1,6,4,1,2,2,1,6,3,2,2,2,3,2,4,4,2,2,3,8,3,
%T 1,1,1,3,2,2,2,2,1,2,3,2,1,1,3,3,4,2,1,1,3,7,7,3,2,4,4,2,1,1,2,4,2,1,
%U 3,4,4,3,1,1,1,2,5,2,3,6,2,2,3,6,5,1,5,3,2,3,2,6,7,2,2,2,6,3,2,3
%N Number of prime factors, with multiplicity, of sum of first n composite numbers.
%F a(n) = A001222(A053767(n)).
%e a(10) = 5 because A053767(10) = 4 + 6 + 8 + 9 + 10 + 12 + 14 + 15 + 16 + 18 = 112 = 2^4 * 7, which has 5 prime factors, with multiplicity.
%p A227314 := proc(n)
%p A001222(A053767(n)) ;
%p end proc: # _R. J. Mathar_, Jul 06 2013
%Y Cf. A001222, A002808, A053767.
%K nonn,easy
%O 1,1
%A _Jonathan Vos Post_, Jul 06 2013
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