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A225116
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a(n) = 3^n*A_{n, 1/3}(-1) where A_{n, k}(x) are the generalized Eulerian polynomials.
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3
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1, 5, 24, 110, 480, 2000, 8064, 32240, 130560, 531200, 2095104, 8030720, 33546240, 156569600, 536838144, 243660800, 8589803520, 244224819200, 137438429184, -28539130347520, 2199021158400, 4960294141952000, 35184363700224, -1015283149035274240, 562949919866880
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OFFSET
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0,2
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LINKS
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FORMULA
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a(n) = 2^(1+n)*(3^n+sum_{j=0..n}(binomial(n,j)*Li_{-j}(-1)*3^(n-j))).
a(n) = 2^(t+1)*(zeta(-t)*(1-2^(t+1))+(2^t-1)). - Peter Luschny, Jul 20 2013
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MAPLE
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EulerianPolynomial := proc(n, k, x) local j; if x = 1 then k^n*n! else (1-x)^(1+n)*(1+add(binomial(n, j)* polylog(-j, x)*k^j, j = 0..n)) fi end:
A225116 := n -> 3^n*EulerianPolynomial(n, 1/3, -1);
seq(round(evalf(A225116(i), 24)), i = 0..24);
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MATHEMATICA
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Table[2^(t+1)*(Zeta[-t]*(1-2^(t+1))+(2^t-1)), {t, 0, 24}] (* Peter Luschny, Jul 20 2013 *)
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PROG
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(Sage)
from mpmath import mp, polylog
mp.dps = 32; mp.pretty = True
def A225116(n): return 2^(1+n)*(3^n+add(binomial(n, j)*polylog(-j, -1) *3^(n-j) for j in (0..n)))
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CROSSREFS
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KEYWORD
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sign
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AUTHOR
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STATUS
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approved
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