OFFSET
1,1
COMMENTS
If 12*h-2523 is a square then some values of 29*h are in this sequence.
It is easy to verify that h is of the form 3*m^2-9*m+217, and therefore 29*(3*m^2-9*m+217) = (16-m)^3+(m+13)^3. [Bruno Berselli, May 10 2013]
LINKS
Vincenzo Librandi, Table of n, a(n) for n = 1..1000
MATHEMATICA
upto[n_] := Block[{t}, Union@Reap[ Do[If[Mod[t = x^3 + y^3, 29] == 0, Sow@t], {x, n^(1/3)}, {y, Min[x, (n - x^3)^(1/3)]}]][[2, 1]]]; upto[106000] (* Giovanni Resta, Jun 12 2020 *)
PROG
(Magma) [n: n in [2..2*10^5] | exists{i: i in [1..Iroot(n-1, 3)] | IsPower(n-i^3, 3) and IsZero(n mod 29)}]; // Bruno Berselli, May 10 2013
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Vincenzo Librandi, May 08 2013
STATUS
approved