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A224222
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a(0)=3; for n>0, a(n) is the smallest prime q not already in the sequence such that the n-th prime p(n) divides a(n-1)+q. If no such prime q exists, the sequence terminates.
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4
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3, 5, 7, 13, 29, 37, 2, 83, 31, 61, 113, 11, 137, 109, 149, 227, 197, 157, 331, 71
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OFFSET
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0,1
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COMMENTS
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a(20) does not exist, so the sequence terminates. A134204 is a similar sequence for which the termination question is unresolved.
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LINKS
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EXAMPLE
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After a(3)=13, to find a(4) we look for a prime q such that the fourth prime, 7, divides 13+q, and q=29 works, since 7 divides 13+29 = 42.
After a(19)=71 we look for a prime q such that p(20)=71 divides 71+q. The only candidate is q=71. Since it is already in the sequence, the sequence terminates.
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CROSSREFS
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KEYWORD
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nonn,fini,full
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AUTHOR
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STATUS
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approved
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