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A222641
Number of iterations in Collatz (3x+1) trajectory of n to reach 1 from the highest term.
2
0, 1, 4, 2, 4, 4, 11, 3, 11, 4, 11, 4, 8, 11, 10, 4, 11, 11, 17, 7, 6, 11, 10, 10, 17, 8, 34, 11, 17, 10, 34, 5, 25, 11, 10, 11, 20, 17, 24, 8, 34, 6, 26, 11, 15, 10, 34, 11, 23, 17, 21, 11, 10, 34, 34, 19, 26, 17, 24, 10, 18, 34, 34, 6, 26, 25, 24, 14, 13, 10
OFFSET
1,3
FORMULA
a(n) = A006577(n) - A220421(n);
EXAMPLE
Collatz trajectory of 5 is 5, 16, 8, 4, 2, 1. Hence, a(5) = 4.
MATHEMATICA
Collatz[n_] := NestWhileList[If[EvenQ[#], #/2, 3 # + 1] &, n, # > 1 &]; Table[c = Collatz[n]; Length[c] - Position[c, Max[c]][[1, 1]], {n, 100}] (* T. D. Noe, Feb 27 2013 *)
CROSSREFS
Sequence in context: A019921 A204617 A061469 * A368437 A258852 A021706
KEYWORD
nonn
AUTHOR
Jayanta Basu, Feb 27 2013
STATUS
approved