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A221219
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Numbers k such that sigma(k) divides Sum_{d|k} sigma(d).
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6
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1, 198, 608, 4680, 11322, 20826, 56608, 60192, 179424, 1737000, 2578968, 3055150, 3441888, 5604192, 6008184, 6331104, 302459850, 320457888, 477229032, 565344850, 579667086, 589459104, 731925000, 766073448, 907521650, 928765600, 3586977576, 3732082848, 6487717600
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OFFSET
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1,2
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COMMENTS
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A066218 is a subsequence of this sequence.
Corresponding values of (Sum_{d|k} sigma(d)) / sigma(k) for numbers k from this sequence: 1, 2, 2, 3, 2, 2, 2, 3, 3, 3, 3, 2, 3, 3, 3, 3, 3, 3, 3, 2, 2, 3, 3, 3, 2, 3, 3, 3, ... - Jaroslav Krizek, Dec 22 2018
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LINKS
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EXAMPLE
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4680 is in the sequence because sigma(4680)=16380, its proper divisors are 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 13, 15, 18, 20, 24, 26, 30, 36, 39, 40, 45, 52, 60, 65, 72, 78, 90, 104, 117, 120, 130, 156, 180, 195, 234, 260, 312, 360, 390, 468, 520, 585, 780, 936, 1170, 1560, 2340 and the sum of their sigma values is 32760. Finally 32760/16380=2.
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MAPLE
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with(numtheory);
for n from 1 to q do a:=divisors(n); b:=add(sigma(a[j]), j=1..nops(a));
if type(b/sigma(n), integer) then print(n); fi; od; end:
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MATHEMATICA
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f1[p_, e_] := (p*(p^(e + 1) - 1) - (p - 1)*(e + 1))/(p - 1)^2; f2[p_, e_] := (p^(e+1) - 1)/(p - 1); aQ[1] = True; aQ[n_] := Module[{f = FactorInteger[n]}, Divisible[Times @@ f1 @@@ f, Times @@ f2 @@@ f]]; Select[Range[10^5], aQ] (* Amiram Eldar, Dec 23 2018 *)
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PROG
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(Magma) [k: k in [1..1000000] | &+[SumOfDivisors(d): d in Divisors(k)] mod SumOfDivisors(k) eq 0] // Jaroslav Krizek, Dec 22 2018
(PARI) isok(n) = (sumdiv(n, d, sigma(d)) % sigma(n) == 0); \\ Michel Marcus, Dec 22 2018
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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