%I #21 Oct 11 2019 03:03:46
%S 2,6,44,741,31574,3488556,1013594692,781364430891,1607468795310696,
%T 8860626201053673385,131236127104980388766388,
%U 5233794723805693339116465076,562910255724699183203714725974687,163474435977817298005300626019111283694
%N Rounded frequency of population with score higher than mean +- n standard deviations.
%H Wikipedia, <a href="http://en.wikipedia.org/wiki/68-95-99.7_rule">68-95-99.7 rule</a>
%e For example, 1 in 2 people have IQ greater than 100, about 1 in 6 people have IQ greater than 115, about 1 in 44 have IQ greater than 130, etc. (assuming normal IQ distribution with mean of 100 and standard deviation of 15)
%t Table[Round[2/(1 - Erf[n/Sqrt[2]])], {n, 0, 15}] (* _T. D. Noe_, Dec 10 2012 *)
%o (MATLAB) round(2/(1-erf(n/sqrt(2))))
%o (PARI) a(n)=round(2/erfc(n/sqrt(2))) \\ _Charles R Greathouse IV_, Dec 10 2012
%Y Cf. A178647.
%K nonn,easy
%O 0,1
%A _Joost de Winter_, Nov 18 2012
%E Extended by _T. D. Noe_, Dec 10 2012