OFFSET
0,1
COMMENTS
LINKS
Alois P. Heinz, Table of n, a(n) for n = 0..4
FORMULA
a(n) = Pell(5^(n+1))/Pell(5^n), where Pell(n) = A000129(n).
Recurrence equation: a(n+1) = 5/2*(a(n)^4 - a(n)^2)*sqrt(4*a(n) + 5) + a(n)^5 + 15/2*a(n)^4 - 25/2*a(n)^2 + 5 with initial condition a(0) = 29.
MATHEMATICA
Table[Fibonacci[5^(n+1), 2]/Fibonacci[5^n, 2], {n, 0, 5}] (* G. C. Greubel, Feb 02 2018 *)
CROSSREFS
KEYWORD
nonn,easy,bref
AUTHOR
Peter Bala, Nov 09 2012
STATUS
approved